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| '''''' import random
'''
初级: 1.已知字符串:“this is a test of Python” a.统计该字符串中字母s出现的次数 b.取出子字符串“test” 提示: str.find('test') c.采用不同的方式将字符串倒序输出 d.将其中的"test"替换为"exam" str.replace() '''
s = "this is a test of Python" count = 0 for c in s: if c == 's': count += 1 print(count)
s = "this is a test of Python" start = s.find('test') end = start + len('test') print( s[start:end] )
s = "this is a test of Python" print(s[::-1])
s2 = "" for i in range(len(s)-1, -1, -1): s2 += s[i] print(s2)
s3 = "" for c in s: s3 = c + s3 print(s3)
s = "this is a test of Python" s2 = "exam" s3 = s.replace('test', s2) print(s) print(s3)
''' 2.已知字符串 a = "aAsmr3idd4bgs7Dlsf9eAF",要求如下 a.请将a字符串的大写改为小写,小写改为大写 ch.lower()小写, ch.upper()大写 b.请将a字符串的数字取出,并输出成一个新的字符串 ch>='0' and ch<='9' c.请统计a字符串出现的每个字母的出现次数(忽略大小写,a与A是同一个字母), 并输出成一个字典。 例 {'a':4,'b':2} d.输出a字符串出现频率最高的字母 e.请判断'boy'里出现的每一个字母,是否都出现在a字符串里。 如果出现,则输出True,否则,则输 出False
''' a = "aAsmr3idd4bgs7Dlsf9eAF"
a2 = "" for c in a: if c>='a' and c<='z': a2 += c.upper() elif c>='A' and c<='Z': a2 += c.lower() else: a2 += c
print(a2)
a = "aAsmr3idd4bgs7Dlsf9eAF" a3 = "" for c in a: if c>='0' and c<='9': a3 += c
print(a3)
a = "aAsmr3idd4bgs7Dlsf9eAF" d = {}
for c in a: if c>='a' and c<='z' or c>='A' and c<='Z': c2 = c.lower()
if c2 not in d: d[c2] = 1 else: d[c2] += 1
print(d)
l = list(d.values())
max_count = max(l)
for k,v in d.items(): if v == max_count: print(k, end=', ')
print()
a = "aAsmr3idd4bgs7Dlsf9eAF"
for c in "boy": if c not in a: print(False) break else: print(True)
''' 注:能不使用系统功能的尽量不要使用,自己实现 中级 1.去除字符串两端的指定字符. s = "hello" ch = "h" # ello ''' s = "hhhhhelhhlohhhhhh" ch = 'h'
i = 0 while i < len(s): if s[i] == ch: s = s[1:] i -= 1 else: break i += 1 print(s)
i = len(s) - 1 while i >= 0: if s[i] == ch: s = s[:-1] else: break i -= 1
print(s)
''' 2.键盘输入一句英文 将每个单词的首字母大写 例如: 输入: hello nice to meet you 转化之后: Hello Nice To Meet You
''' s = "hello nice to meet you" s2 = "" for i in range(len(s)): if i==0 or s[i-1]==" ": s2 += s[i].upper() else: s2 += s[i]
print(s2)
''' 3.输入一个字符串,压缩字符串如下aabbbccccd变成a2b3c4d1 ''' s = "aabbbccccd" d = {} for c in s: if c not in d: d[c] = 1 else: d[c] += 1
print(d)
s2 = "" for k, v in d.items(): s2 = s2 + k + str(v)
print(s2)
'''
4.完成猜拳游戏 ----------------------------- 请输入你的选择: 1. 石头 2. 剪刀 3. 布 ----------------------------- 你的选择是【布】, 电脑的选择是【石头】 恭喜你获得了胜利!
'''
print('''----------------------------- 请输入你的选择: 1. 石头 2. 剪刀 3. 布 -----------------------------''')
while True: me = int(input("请出拳(输入编号):")) computer = random.randint(1,3) print(me, computer)
if me-computer == -1 or me-computer == 2: print("恭喜你获得胜利!") break elif me == computer: print("平手") else: print("我输了")
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